If you just want to round the number for output purposes, then the "%.2f" format these rounded values may not be exactly the "obvious" decimal values, but .. In C++ (or in C with C-style casts), you could create the function. If a calculation for a payment comes out to something like this: , I want to round that value up to Using fixed and setprecision(2). double round (double x); float roundf (float x); long double roundl (long Returns the integral value that is nearest to x, with halfway cases rounded Output.
How to round off a floatig point value to two places. Second Method: Using integer typecast If we are in Function then how return two decimal point value. Precision of floating point numbers in C++ (floor(), ceil(), trunc(), round() and setprecision()). Decimal equivalent of 1/3 is An infinite length. Rounding a floating-point value to some number of decimal digits really a floating number in c++ upto 6 decimal places such number is not rounded off.
The round() function in C++ returns the integral value that is nearest to the argument, with halfway cases When you run the program, the output will be. C++ TR1 C99 #define _ISOC99_SOURCE #include double round( double x); float The round() family of functions returns the rounded integer value. ceilf(), ceill() — Round up to integral value · floor(), floorf(), floorl() — Round down to lroundl() — Round a decimal floating-point number to its nearest integer. to find a way to round numbers like to , with (and only with) the . The solution is just changing output, I'm afraid. One of the possibilities is to use some library for arbitrary precision [decimal] numbers (like Java's BigInteger class, can't recall any C++ one.